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Nutka1998 [239]
2 years ago
11

Evaluate the expression (5 + 2i) - (-3- i) and write the result in the form a +bi.

Mathematics
1 answer:
andre [41]2 years ago
4 0
B because I took the test
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WARM-UP Solutions
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3 years ago
The line x+ 2y = 9 intersects the curve xy + 18 = 0 at the points A and B. Find the coordinates of A and B.
victus00 [196]
Subtracting the second equation by 18 on both sides, we have xy=-18. Next, we divide both sides by x to get y=-18/x  Plugging that into the first equation, we have x+2(-18/x)=9. Multiplying both sides by x, we get x^2-36=9x. After that, we subtract both sides by 9x to get x^2-9x-36=0. Finding 2 numbers that add up to -9 but multiply to -36, we do a bit of guess and check to find the answers to be -12 and 3. Factoring it, we get 
x^2-12x+3x-36=x(x-12)+3(x-12)=(x+3)(x-12). To find the x values, we have to find out when 0=(x+3)(x-12). This is simple as when you multiply 0 with anything, it is 0. Therefore, x=-3 and 12. Plugging those into x=-18/y, we get x=-18/y and by multiplying y to both sides, we get xy=-18 and then  we can divide both sides by x to get -18/x=y. Plugging -3 in, we get -18/-3=6 and by plugging 12 in we get -18/12=-1.5. Therefore, our points are (-3,6) and (12, -1.5)
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3 years ago
Hey guys, I'm relearning some Algebra and was confused about this problem. In the equation, the problem was divided by 3. This m
spayn [35]

Answer and Step-by-step explanation:

The signs didn't really "swap". Instead, the whole function was divided by -1, or we could say the function was divided by -3. That would turn:

-18x² - 15x + 3 = 0

into

(-18 / -3)x² - (15 / -3)x + (3 / -3) = 0

6x² + 5x - 1 = 0

And that gives the "swapped signs".

4 0
3 years ago
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