Answer:
your answer is given below
Explanation:
Take it stepwise, and you are going to have to look up the various heat values.
You have 36.5grams of ice, presumably at 0C. You will need to add heat to take the ice at 0 C to water at 0 C. (Latent heat of melting) Then you add in a different heat value to take the water at 0 C to water at 82.3 C. (Specific heat of water)
Add the two heat amounts together.
Answer:
P(O₂) = 287.41 mmHg
P(O₂) = 413.59 mmHg
Explanation:
Given data:
Total pressure = 701 mmHg
Mass of methane = 2.75 g
Mass of oxygen = 3.45 g
Partial pressure of each gas = ?
Solution:
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 2.75 g/ 16 g/mol
Number of moles = 0.17 mol
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 3.45 g/ 32 g/mol
Number of moles = 0.12 mol
Total number of moles = 0.12 mol + 0.17 mol = 0.29 mol
Partial pressure of oxygen:
P(O₂) = [ moles of oxygen / total moles ] × total pressure
P(O₂) = [0.12 / 0.29 ] × 701 mmHg
P(O₂) = 0.41 × 701 mmHg
P(O₂) = 287.41 mmHg
Partial pressure of methane:
P(O₂) = [ moles of oxygen / total moles ] × total pressure
P(O₂) = [0.17 / 0.29 ] × 701 mmHg
P(O₂) = 0.59 × 701 mmHg
P(O₂) = 413.59 mmHg
Hund's Rule<span>. </span>Hund's rule<span>: every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin. so D. is the answer</span>
Answer:
One mole of CO2 has mass of 44 g and 32 g of O2. So 16 g of O2 have 22 g of CO2 or 0.5 moles of it.
brainliest plz
Explanation: