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Ksju [112]
3 years ago
6

Which sulfate is soluble?

Chemistry
2 answers:
Alexandra [31]3 years ago
8 0

Answer:

Gold(II) sulphate is soluble

Explanation:

According to solubility rule, all sulphates are soluble except CaSO_{4},SrSO_{4},BaSO_{4},Hg_{2}SO_{4},HgSO_{4},PbSO_{4} and Ag_{2}SO_{4}

One of the reason for gold sulphate to be a soluble salt is that both gold(II) and sulphate are bigger in size. Therefore their lattice energy is low as lattice energy is inversely proportional to sum of radius of cation and anion.

Hence lattice structure of gold sulphate can be easily disrupted and make constituting ions to get soluble.

Dafna1 [17]3 years ago
4 0

The Answer is B. gold(ll) sulfate

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Homes in rural areas where natural gas service is not available often rely on propane to fuel kitchen ranges. The propane is sto
Neporo4naja [7]

Answer:

2666.7 hours

Explanation:

The key to solve this problem is that we are given the propane gas consumed in one hour by giving us the information of the volume consumed at 1 atm, 298 K (25 +273). Using the gas law we can calculate the rate of consumption  of propane per hour, and from here we can calculate its mass and converting it to gallons and finally diving the 400 gallos by this number.

PV = nRT ∴ n = PV/RT

n = 1 atm x 165 L/ (0.08206 Latm/kmol x 298 K ) = 6.75 mol propane

Mass propane :

6.75 mol x 44 g/mol = 296.88 g

convert this to Kg:

296.88 g/ 1000 g/Kg = 0.30 Kg

calculate the volume in liters this represents by dividing by the density:

0.30 Kg / 0.5077 Kg/L =  0.59 L

changing this to gallons

0.59 L x  1 gallon/3.785 L = 0.15 gallon

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400 gallon/ 0.15 gallon/hr = 2666.7 hr

6 0
3 years ago
How many grams of Chromium(III) nitrate are produced when Chromium reacts with 0.85 moles of Lead(IV) nitrate to produce chromiu
mina [271]

Grams of Chromium(III) nitrate produced : 268.95 g

<h3>Further explanation</h3>

Given

0.85 moles of Lead(IV) nitrate

Required

grams of Chromium(III) nitrate

Solution

Reaction

Balanced equation :

<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>

From the equation, mol ratio of Pb(NO₃)₄  : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃

mol Cr(NO₃)₃ =

\tt \dfrac{4}{3}\times 0.85=1.13

Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :

mass = mol x MW

mass = 1.13 x 238.0108

mass = 268.95 g

7 0
3 years ago
2A(g) + B(l) ⇌ 3C(aq) + D(s)
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Answer:

B

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Explanation:

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