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nirvana33 [79]
3 years ago
8

HI GUYS!! PLS HEL PME I NEED HELP, here is the question

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Answer and Step-by-step explanation:

We have to use the image to help us answer this question.

We see that there are 8 big fish in the tank, and 10 small fish in the tank.

So, for the first part, it would be:

There are 8 big fish for every <u>10</u> small fish.

For when there are 4 big fish, we need to divide 10 by 2, since 8 divided by 2 is 4.

10 ÷ 2 = 5

So,

There are 4 big fish for every <u>5</u> small fish.

I hope this helps!!

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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Least common multiple
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What is the value of tanØ
mr_godi [17]

Answer:

tan ∅ = 24 / 7

Step-by-step explanation:

cos ∅ = 7 / 25

sin^2 ∅ + cos^2 ∅ = 1

sin^2 ∅ + (7 / 25)^2 = 1

sin^2 ∅ = 1 - 49 / 625

sin^2 ∅ = 625 - 49 / 625

sin^2 ∅ = 576 / 625

sin ∅ = root 576 / 625

sin ∅ = 24 / 25

tan ∅ = sin ∅ / cos ∅

tan ∅ = 24/25  /  7/25

Therefore, tan ∅ = 24 / 7

OPTION 4.   24 / 7

8 0
3 years ago
How many ways can 10 students line up in a food counter?
KonstantinChe [14]

Answer:

for the first student in the line there are 10 choices,then for the 9 choices left,for the third 8 choices left and so on...

so its 10x9x8x7x6x5x4x3x2x1=3628800

Step-by-step explanation:

sana makatulong

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20-%203%20%2B%205i%20%20%5Cdiv%20%20-%203%20-%204i" id="TexFormula1" title=" - 3 + 5i \div
Likurg_2 [28]

Answer:

\frac{-11}{25}+\frac{-27}{25}i given you are asked to simplify

\frac{-3+5i}{-3-4i}

Step-by-step explanation:

You have to multiply the numerator and denominator by the denominator's conjugate.

The conjugate of a+bi is a-bi.

When you multiply conjugates, you just have to multiply first and last.

(a+bi)(a-bi)

a^2-abi+abi-b^2i^2

a^2+0         -b^2(-1)

a^2+-b^2(-1)

a^2+b^2

See no need to use the whole foil method; the middle terms cancel.

So we are multiplying top and bottom of your fraction by (-3+4i):

\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}

So you will have to use the complete foil method for the numerator. Let's do that:

(-3+5i)(-3+4i)

First: (-3)(-3)=9

Outer::  (-3)(4i)=-12i

Inner: (5i)(-3)=-15i

Last: (5i)(4i)=20i^2=20(-1)=-20

--------------------------------------------Combine like terms:

9-20-12i-15i

Simplify:

-11-27i

Now the bottom (-3-4i)(-3+4i):

F(OI)L (we are skipping OI)

First:-3(-3)=9

Last: -4i(4i)=-16i^2=-16(-1)=16

---------------------------------------------Combine like terms:

9+16=25

So our answer is \frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i

6 0
3 years ago
Find the exact length of the curve. y2 = 4(x + 1)3, 0 ≤ x ≤ 1, y &gt; 0
mylen [45]
We can find this using the formula: L= ∫√1+ (y')² dx

First we want to solve for y by taking the 1/2 power of both sides:

y=(4(x+1)³)^1/2
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Now, we can take the derivative using the chain rule:

y'=3(x+1)^1/2

We can then square this, so it can be plugged directly into the formula:

(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9

We can then plug this into the formula:

L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765

The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
6 0
4 years ago
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