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Karo-lina-s [1.5K]
3 years ago
11

PLZ HELPMarcus spent 10 hours doing his homework last week. This week he spent 11 hours doing homework. He says that he spent 11

0% more time doing homework this week. Is he correct? Show your work to justify your decision.
Mathematics
1 answer:
leva [86]3 years ago
5 0
This problem is a more like of a percentage increase problem. First, subtract 11 hours by the original hours which is 10 hours. Using mental math, subtracting 11 by 10 would be 1, obviously. Take the outcome of 1 and divide it by the hours he did last week which is 10. 1 divided by 10 would be equal to .1. Convert the decimal to a percentage and then you would get 10% and add it to 100%. So, yes, he is in fact correct.
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The graph of a system of equations with the same slope and the same y-intercepts will have no solutions.
Rasek [7]
If 2 equations have the same y-intercept, they are overlapping, which means they have infinite solutions. So there is no way that 2 equations with the same y-intercept will have no solution. Thus your answer is: C)Never. 
4 0
3 years ago
Read 2 more answers
The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:
deff fn [24]

Step-by-step explanation:

Given equation of circle is,

{x}^{2}  +  {y}^{2}  - 6y - 12 = 0 \\ by \: compairing \: it \: with \:   \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f=  - 6 \\ or \: f=  - 3 \\ c =  - 12

again the another form of circle is,

{x}^{2}  +  {(y - k)}^{2}  = 21 \\ or \:  {x}^{2}  + {y}^{2}  - 2ky +  {k}^{2}  - 21 = 0 \\ by \: compairing \:it \: with \:  \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get  \\ g = 0 \\f =  - k \\ c =  {k}^{2}  - 21

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0
3 years ago
What is the percent of decrease from 320 to 32?<br><br> A.)10%<br> B.)90%<br> c.)100%<br> D.)288%
torisob [31]

the answer will become 10%

5 0
3 years ago
Evaluate for the given value of the variable 1/2 X s for s = 3/10
Pani-rosa [81]
Just plug in the equation, 1/2*3/10 and multiply it out. Thus, 1*3=3 and 2*10=20
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8 0
2 years ago
The figure below can be used to prove the Pythagorean Theorem. Use the drop-down menus to complete the proof.
Lynna [10]

ANSWER :

1. 2ab + c^2

2. (a + b)^2 or (a^2 + 2ab + b^2)

3. 2ab

EXPLANATION :

Recall that the area of a triangle is 1/2 base x height.

and the area of a square is the square of its side.

From the problem, we have 4 congruent triangles.

The area of four triangles is :

\begin{gathered} A=4\times\frac{1}{2}(ab) \\ A=2ab \end{gathered}

The area of the square is :

A=c^2

Then the total area will be :

2ab+c^2

It is equivalent to the area of the whole square in which the side is (a + b)

So that's :

A=(a+b)^2\quad or\quad(a^2+2ab+b^2)

Since both expressions are equal, we can equate them :

\begin{gathered} 2ab+c^2=a^2+2ab+b^2 \\ \text{ Subtracting 2ab from both sides :} \\ 2ab+c^2-2ab=a^2+2ab+b^2-2ab \\ c^2=a^2+b^2 \end{gathered}

3 0
1 year ago
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