Answer:
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375 as a decimal number.
Answer: 9/4a^2|b^3|c^4
Step-by-step explanation:
81/16
Square root(81) = 9
Square root(16) = 4
9/4
Since 4 is the index of the radical, all of the exponents divide by 4
(index 4)a^8 = a^2
(index 4)b^12 = b^3
(index 4)c^16 = c^4
Now put the variables together to get the answer:
9/4a^2|b^3|c^4
Answer:
1/3x^11
Step-by-step explanation:
1/3x^11 is the answer
Answer:
6 times whatever x is would be greater that -54
