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Dafna1 [17]
3 years ago
13

5* 2+3.(4+2)-4(5* 2)

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

Answer:

5 * 2 + 3(4 + 2) - 4(5 * 2)

= 10 + 3(6) - 4(10)

= 10 + 18 - 40

= 28 - 40

= -12

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Some one help if answer is right I’ll give u brainliest<3
Varvara68 [4.7K]

Answer:

I think its A to the third plus 12 to the third power

6 0
3 years ago
Read 2 more answers
19. answer this question.​
Irina-Kira [14]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ final = original x multiplier^n

n is the number of years

Substitute the values in:

final = 3800 x 1.054^3

final = 4449.440763

The closest answer is A

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0
3 years ago
Read 2 more answers
A school paid $31.25 for each calculator. If the school bought x calculators, how much did they pay?
Katyanochek1 [597]

Answer:

31.25×

Step-by-step explanation:

suppose that the value of x was 3 . that would mean that they bought 3 calculators .

if one calculator is $31.25 then 3 would be $31.25× 3

the same rule would apply for x

7 0
3 years ago
._. Help me please I’m putting my faith in this app.
IRINA_888 [86]
Vas happenin!
Hope your day is going well
I think it’s A
Sorry if it’s wrong
Hope this helps *smiles*
8 0
2 years ago
How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.
stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula \displaystyle nCr=\frac{n!}{r!(n-r)!} which describes the number of ways we can choose r objects given n possible choices. So, if n=7 and r=4, then:

_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35

Hence, the teacher can make 35 different geometry quizzes.

3 0
2 years ago
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