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3 years ago

5* 2+3.(4+2)-4(5* 2)

Mathematics

1 answer:

Studentka2010 [4]3 years ago

8 0

Answer:

5 * 2 + 3(4 + 2) - 4(5 * 2)

= 10 + 3(6) - 4(10)

= 10 + 18 - 40

= 28 - 40

= -12

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The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?

Whitepunk [10]

If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
[e^(2+h) − e^2]/h = [e^2(e^h−1)]/h

so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:

=e^2

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3 years ago

Write the missing decimal so that each pair adds to 1. 2/5+decimal =1

I am Lyosha [343]

Answer:

0.6

Step-by-step explanation:

We can get the answer by subtracting the decimal by one.

2/5 = 0.4

1 - 0.4 = 0.6

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2 years ago

Consider the continuous random variable x, which has a uniform distribution over the interval from 110 to 150. The probability t

Virty [35]

Answer:

The probability that x will take on a value between 120 and 125 is 0.14145

Step-by-step explanation:

For uniform distribution between a & b

Mean, xbar = (a + b)/2

Standard deviation, σ = √((b-a)²/12)

For 110 and 150,

Mean, xbar = (150 + 110)/2 = 130

Standard deviation, σ = √((150-110)²/12 = 11.55

To find the probability that x will take on a value between 120 and 125

We need to standardize 120 & 125

z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87

z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43

P(120 < x < 125) = P(-0.87 < x < -0.43)

We'll use data from the normal probability table for these probabilities

P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145

Hope this Helps!!!

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Answer:

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