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3 years ago

11

Pls pls pls help pls

2 answers:

Alona [7]3 years ago

6 0

Answer:

Diagonal =26.11 units

Step-by-step explanation:

Anon25 [30]3 years ago

5 0

I hope this might help u

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Which property of equality could be used to solve -3x = 348? A. addition property B. subtraction property C. division property D

gizmo_the_mogwai [7]

Answer:

B:subtraction property

Step-by-step explanation:

3 0

3 years ago

Solve for x. 3(3x - 1) + 2(3 - x) = 0

olga nikolaevna [1]

The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
= - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can always use this method for solving problems that are similar in type without requiring any help from outside. </span>

8 0

3 years ago

If O N = 8 x − 8 , L M = 7 x + 4 , N M = x − 5 , and O L = 3 y − 6 , find the values of x and y for which LMNO must be a paralle

posledela

Answer:

$x=12\\y=\frac{13}{3}$

Step-by-step explanation:

For it to be a parallelogram, opposite sides have to be of same length.

OL = NM, and
ON = LM

Using the expressions given, we can make 2 equations:

<u>Equation 1:</u>

$OL=NM\\3y-6=x-5\\-x+3y=1$

<u>Equation 2:</u>

$ON=LM\\8x-8=7x+4\\$

<em>Solving equation 2, we have x:</em>

$8x-8=7x+4\\8x-7x=4+8\\x=12$

<em>Plugging this value of x into equation 1, we can solve for y:</em>

$-x+3y=1\\-(12)+3y=1\\-12+3y=1\\3y=13\\y=\frac{13}{3}$

So,

$x=12\\y=\frac{13}{3}$

7 0

4 years ago

Peter weighs is 105 kg. His wants to lose 500 g per week. How many weeks will it take for him to have

ziro4ka [17]

Answer:

30 weeks

Step-by-step explanation:

105-90

=15 kg

15kg= 15000g

15000g/500g

=30 weeks

plz mark me as brainliest.

6 0

3 years ago

The fuel efficiency (mpg rating) for cars has been increasing steadily since 1980. The formula for a car's fuel efficiency for a

Lisa [10]

Answer:

a) In the interval of [1980,1983].

b) In the interval of [1991, 1996].

Step-by-step explanation:

Fuel efficiency:

The fuel efficiency, for the cars, in x years after 1980, is given by:

$E(x) = 0.36x + 15.9$

15.9 is the fuel efficiency in 1980.

a. In what years was the average fuel efficiency for cars less than 17 mpg (in interval form)?

From 1980 to:

$E(x) < 17$

$0.36x + 15.9 < 17$

$0.36x < 1.1$

$x < \frac{1.1}{0.36}$

$x < 3.06$

3.06 = 1980 + 3 = 1983. So

In the interval of [1980,1983].

b. In what years was the average fuel efficiency for cars more than 20 mpg (in interval form)?

From x until 1996.

$E(x) > 20$

$0.36x + 15.9 > 20$

$0.36x > 4.1$

$x > \frac{4.1}{0.36}$

$x > 11.38$

11.38 = 1980 + 11 = 1991. So

In the interval of [1991, 1996].

4 0

3 years ago