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Alinara [238K]
3 years ago
11

What is the coeficient of a+3b

Mathematics
1 answer:
stiks02 [169]3 years ago
6 0

Answer:

The coefficient is 3

Step-by-step explanation:

The definition of a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4xy).

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Y=4x-1<br>Y-2=x <br>i need help substitution method​
Anton [14]

Answer:

x = 1, y = 3

Step-by-step explanation:

x = y - 2, so y = 4 (y - 2) -1

solve normally now

y = 4 (y - 2) -1

y = 4y - 8 - 1 (distribute)

y = 4y - 9 (simplify)

+9 -y -y +9

9 = 3y

3 = y

y - 2 = x

(3) - 2 = x

x = 1

7 0
3 years ago
Show how to make a ten to find 12-4. Write the number sentence
aliya0001 [1]
Subtract 2 from 12. 12-2 is 10. You can subtract 10 with 4, and then add 2. (10-4)+2=8.
7 0
3 years ago
Read 2 more answers
Please help ^<br> |<br><br> 10 Points!!!!
alexdok [17]

Answer:

whats the q or am i blind

Step-by-step explanation:

4 0
4 years ago
Francis ran 2 1/2 miles in 7/12 of an hour. How many miles can francis run in one hour?
nevsk [136]

7/12 of 1 hour:

1 hour = 60 min.

7/12 * 60

7 * 5 = 35

Francis ran 2 1/2 miles in 35 min.

2 1/2 = 5/2


5/2 miles = 35 min

x miles = 60 min

(Cross Multiply)


5/2 * 60 = 35x

5 * 30 = 35x

150 / 35 = x

x = 30 / 7 = 4 2/7 miles


Francis ran 4 2/7 miles in one hour.


8 0
3 years ago
Read 2 more answers
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

4 0
3 years ago
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