The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
<h3>4) Substitute the value of y</h3>
<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
Answer: The distance around the lot is given by
Step-by-step explanation:
Since we have given that
Length of rectangular lot is given by
Width of rectangular lot is given by
We need to find the distance around the lot.
As we know the formula for "Perimeter of rectangle":
Hence, the distance around the lot is given by
The rule for this one is called the difference of squares
A^2 - b ^2 = (a+b)(a-b)
Using this rule
N^2 - 62 = (n+ sqrt(62)) (n - sqrt(62))
The solution for this one is to make the statement = 0
0 = (n+ sqrt(62)) (n - sqrt(62))
N can either be +- sqrt(62)
(-1,1) (6,9)
distance = root (x1-x2)²+(y1-y2)²
so root (-1-6)²+(1-9)²= root 113 or 10.6 ≈11
the answer is B. 11.18 units
