Select all the expressions that have a value of 22

2. Find the lateral area and surface area of the prism. 4 cm 5 cm 4 cm 3 cm

Vaselesa [24]

Answer:

Lateral = 48 cm squared and Surface area = 60 cm squared

Step-by-step explanation:

Lateral surface area = 4 x 4 + 5x4( Slope) + 4 x 3 (Cross section x2) = 48

Surface area: Lateral + 4x3(base)

4 0

3 years ago

Which statement proves that this angle pair is the Corresponding Angles Theorem. Criteria Laval

anzhelika [568]

Answer:

its jess

here is ur ans

first option is your answer

• ANGLE 2 AND ANGLE 6 ARE CONGRUENT BECAUSE THEY ARE CORRESPONDING ANGLES.

5 0

3 years ago

What is the slope and y-intercept of line q graphed below?

beks73 [17]

The correct answer is C) 1/3 and (0, 1)

The y-intercept part is somewhat simple. In order for it to be a y-intercept, the x value of the ordered pair must be 0. That is only true in B and C, therefore they are the only possible answers.

To find the slope, we must choose two points on the line and use the slope formula. We can start by using the y-intercept (0, 1) and also (3, 2). Now we use the slope formula.

m = (y2 - y1)/(x2 - x1)

In this equation m is equal to slope, the first point is (x1, y1) and the second point is (x2, y2)

m = (y2 - y1)/(x2 - x1)

m = (2 - 1)/(3 - 0)

m = 1/3

Now knowing the slope, you can match this with answer C.

3 0

3 years ago

koda Buys 0.75 kg of cortos,which ia 5times the mas of the union he also Buys. How much does the union weigh?

kari74 [83]

Answer:

0.15kg

Step-by-step explanation:

Given data

We are told that

0.75 kg of cortos weights 5times the mas of the onion

We want to find the mass of 1 onion

Hence

0.75 kgcortos = 5 onions

x cortos = 1 onions

x= 0.75/5

x= 0.15kg

Hence 1 onion will weigh 0.15kg

4 0

3 years ago

A sample of 12 radon detectors of a certain type was selected, and each was exposed to 100 pCI/L of radon. The resulting reading

valkas [14]

Answer:

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu \neq 100$

$t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921$

$p_v =2*P(t_{11}$

Step-by-step explanation:

1) Data given and notation

Data: 105.6, 90.9, 91.2, 96.9, 96.5, 91.3, 100.1, 105.0, 99.6, 107.7, 103.3, 92.4

We can calculate the sample mean and deviation for this data with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

The results obtained are:

$\bar X=98.375$ represent the sample mean

$s=0.6.109$ represent the sample standard deviation

$n=12$ sample size

$\mu_o =100$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal to 100pCL/L, the system of hypothesis are :

Null hypothesis: $\mu = 100$

Alternative hypothesis: $\mu \neq 100$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{98.375-100}{\frac{6.109}{\sqrt{12}}}=-0.921$

4) P-value

First we need to find the degrees of freedom for the statistic given by:

$df=n-1=12-1=11$

Since is a two sided test the p value would given by:

$p_v =2*P(t_{11}$

5) Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significant different from 100 at 5% of significance.

3 0

3 years ago

Select all the expressions that have a value of 22 - 33 +29.