Answer:
B. 21
Step-by-step explanation:
The fractions are there to just make the problem seem complicated, but just rewrite it without the fractions.
"What is a common multiple for 7 and 3?"
In this problem it's easy, all you have to do is guess and check.
A: A doesn't work. 7 is not a factor of 18.
B: B works! Both 3 and 7 are factors of 21.
C: C doesn't work. 7 is not a factor of 3.
D: D doesn't work. Neither are a factor of 4.
They only leave us with one solution, B.
In the question we are given three lines L,M and N such that:
Line L is perpendicular to M
and line L is parallel to line N
so the option is (C) M is perpendicular N
Step-by-step explanation
We are given three lines L,M and N such that:
- Line L is perpendicular to M
- Line L is parallel to line N
<u>We know that when one line parallel to the second line and is perpendicular to the third line then the second line is also perpendicular to the third line.</u>
<u></u>
So,the answer is (C) M is perpendicular N
Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,
Let us take square root of both sides of our equation.
Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
2. y=12000(.06)4x<span>
3. y=300(.08)5x
Hope this helps</span>
Answer:
40 girls 20 boys i think / guess
Step-by-step explanation:
