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Rashid [163]
3 years ago
11

Please help me on this!

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

9*572=5148

Step-by-step explanation:

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Hey how to do this and what the answer​
frez [133]

Answer:

5x + y - 4 = 0

Step-by-step explanation:

When we are given two points and are asked to find the equation of the line we use the two - point form.

Two - point form: $ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} $.

where: $ (x_1,y_1) $ and $ (x_2,y_2) $ are the two points on the line.

Given the two points are: (5,21) and (-5,-29).

Substituting in the two point form:

⇒  $ \frac{y - 21}{-29 - 21} = \frac{x - 5}{-5 -5} $

$ \implies \frac{y - 21}{-50} = \frac{x - 5}{-10} $

$ \implies y - 21 = 5x - 25 $

⇒                              5x + y - 4 = 0

8 0
3 years ago
Which are are solutions for x^2 + 5x – 1 > 6
Eddi Din [679]

Answer:

it might be b and d

Step-by-step explanation:

6 0
3 years ago
Helllllllllllppppppppp
andrew11 [14]
-1/2 because slope is the rise over the run. If you count on the grid from one point on the line to another you go up one and 2 to the left meaning the slope is 1/2, buttttt when the line decreases going to the right, it has a negative slope so you just add a - sign in front
3 0
3 years ago
Read 2 more answers
Two opposite numbers are 18 units away from each other. What are the numbers?
Oksanka [162]

Answer:

-4 and 4

Step-by-step explanation:

You count between the zeros as when you jump on a number line or just don't count the zero

-4, -3, -2 ,-1, 0, 1, 2 ,3, 4

Hope this helps

5 0
2 years ago
Which is the solution to the inequality y+15 <3?
Paraphin [41]

To solve an equation or inequality, you can add the same value to both sides of the expression. Here, it is convenient to choose that value to be the opposite of the constant (+15) added to y, so that constant is replaced by zero.


  y + 15 - 15 < 3 - 15 . . . . . we have added -15 to both sides

  y < -12 . . . . . . . . . . . . . . . the result of simplifying. This is your solution.

6 0
3 years ago
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