
2) 5.625 mg will be left
Explanation:
1) Half-life = 17.5 days
initial amount of Arsenic-74 = 90 mg
To get the equation, we will use the equation of half-life:


2) we need to find the remaining amount of Arsenic-74 after 70 days
t = 70

So after 70 days, 5.625 mg will be left
X. Y
12 —> 4
8 —> 8/3
13 —> 13/3
Substitute x values for y.
y = 1/3(12)
y=4
Answer:
w = 5
y = 4
Step-by-step explanation:
w+y=9
3w-y=11
4w = 20
w = 5
y = 4
Well 32 divided by 8 would be 4 so... 32 x 4 would be 128 so 128 times. If it’s not correct I’m really sorry.