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dusya [7]
3 years ago
5

I need help with matrix please please please anyone to help me.....?​

Mathematics
1 answer:
erica [24]3 years ago
3 0

Answer:

what can i help you

Step-by-step explanation:

if i can i will help you

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Help me out please, im only typing this much because its making me...
Genrish500 [490]

Answer:

B.x^{2} +2x-8

Step-by-step explanation:

Here the best method to solve is by substituting the end values of the set in each option , otherwise it will a time consuming problem.

Now substitute x=-4 in all the options

A.x^{2} -2x-8

16+8-8=16>0

so out of option A and C option C is correct.

B.x^{2} +2x-8

16-8-8=0 which means for the values of x>-4 x^{2} +2x-8is less than 0

Now substitute x=2 in all the options

A.x^{2} -2x-8

4-4-8=-8<0 . so option A and C both are incorrect.

B.x^{2} +2x-8

4+4-8=0 which means for the values of x<2 x^{2} +2x-8 is less than 0

Therefore the correct option is B

6 0
4 years ago
X^2-6x+5=0 solve with quadratic formula
Yuliya22 [10]

Answer: x1  = 5

               x2 = 1

Step-by-step explanation:

1. Identify the coefficients

2. Move the constant to the right side of the equation and combine

3.  Complete the square

4. Solve for x

7 0
2 years ago
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zaharov [31]
Use a ruler for this problem. Take a picture of the measurement & then I could help you.
8 0
3 years ago
The packaging lists a model airplane’s length as 10.5 in. It also gives the scale as 1:83. What is the length of the actual airp
Lana71 [14]
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6 0
3 years ago
(1 point) Find two unit vectors orthogonal to a=⟨4,5,0⟩a=⟨4,5,0⟩ and b=⟨0,1,−3⟩b=⟨0,1,−3⟩ Enter your answer so that the first no
Anni [7]

Answer:

 First vector

V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}

Second vector

V=- \dfrac{-15i+12j+4k}{\sqrt{385}}

Step-by-step explanation:

Given that

Vector a ,  a= 4 i + 5 j + 0 k

Vector b , b= 0 i + 1 j  - 3 k

The orthogonal vector V is given as

V = a x b

V is the cross product of the above two vector which is orthogonal to the vectors a and b.

V=\begin{vmatrix}i & j & k\\ 4 & 5 & 0\\  0& 1 &-3 \end{vmatrix}\\V=i(-15-0)-j(-12-0)+k(4-0)\\V=-15i+12j+4k

The unit vectors

V=\pm \dfrac{-15i+12j+4k}{\sqrt{15^2+12^2+4^2}}\\\\V=+\dfrac{-15i+12j+4k}{\sqrt{385}}\\V=-\dfrac{-15i+12j+4k}{\sqrt{385}}

First vector

V=+ \dfrac{-15i+12j+4k}{\sqrt{385}}

Second vector

V=- \dfrac{-15i+12j+4k}{\sqrt{385}}

5 0
3 years ago
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