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yulyashka [42]
3 years ago
6

Simplify these expressions. 1.) 7log7 ^x 2.) log3 3^2x

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

okay for number one your answer is 7^7^x

for number two it’s confusing

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What is the base five representation of The number 219
ICE Princess25 [194]

assuming 219_{10}

Then the column values for base five here are

5³  5²  5^{1}  5^{0}

We can get 1 × 5³ = 125 → 219 - 125 = 94

We can get 3 × 5² = 75 → 94 - 75 = 19

We can get 3 x 5^{1} → 19 - 15 = 4

and 4 = 4 × 5^{0}

Thus 219_{10} = 1334_{5}

As a check

(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219


3 0
2 years ago
3x – 2y = 17 <br> –2x – 5y = 14 <br> Solve using Elimination Please show work
OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

3x- 2y = 17\\-2x -5y = 14

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3

Multiplying equation 2 by 3

3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4

Adding equation 3 and 4

(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\

Putting y = -4 in equation 1

3x-2(-4) = 17\\3x+8 = 17\\3x = 17-8\\3x = 9\\\frac{3x}{3} = \frac{9}{3}\\x = 3

Hence,

The solution is x=3 , y=-4 or (3,-4)

3 0
2 years ago
Can someone help please!!
Tpy6a [65]

Answer:

Step-by-step explanation:

3 0
3 years ago
What is the equation in point-slope form of the line that passes through the points (7, 5)(7, 5) and (−4, −1)(−4, −1) ? y+4=116(
Alex Ar [27]
(7,5)(-4,-1)
slope = (-1-5) / (-4-7) = -6/-11 = 6/11

y - y1 = m(x - x1)
slope(m) = 6/11
(-4,-1)...x1 = -4 and y1 = -1
now we sub...pay close attention to ur signs
y - (-1) = 6/11(x - (-4) ...not done yet...
y + 1 = 6/11(x + 4) <===
6 0
2 years ago
Read 2 more answers
(Geometry) The answers are x = 15 and y = 9 but I don't know how. Help me understand this
Kryger [21]

Check the picture below.

\bf \stackrel{\measuredangle DAC}{4y+2x}~~=~~\stackrel{\measuredangle BCA}{9y-x}\implies 2x=5y-x\implies 3x=5y\implies \boxed{x=\cfrac{5y}{3}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\measuredangle DAB}{[(4y+2x)+35]}~~+~~\stackrel{\measuredangle ADC}{5x+4}~~=~~180\implies 4y+2x+5x+39 = 180 \\\\\\ 4y+7x+39=180\implies 4y+7x=141\implies \stackrel{\textit{substituting "x"}}{4y+7\left( \boxed{\cfrac{5y}{3}} \right)} = 141

\bf 4y+\cfrac{35y}{3}=141\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3\left( 4y+\cfrac{35y}{3} \right)=3(141)}\implies 12y+35y=423 \\\\\\ 47y=423\implies y=\cfrac{423}{47}\implies \blacktriangleright y = 9 \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that}}{x=\cfrac{5y}{3}}\implies x = \cfrac{5(9)}{3}\implies \blacktriangleright x = 15 \blacktriangleleft

4 0
3 years ago
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