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MrRissso [65]
3 years ago
12

Cassandra obtains a loan with simple interest to buy a car that costs $8,500. If Cassandra pays $1,020 in interest during the fo

ur-year term of the loan, what was the rate of simple interest? I need it in percent. For example 74%.
Mathematics
2 answers:
Fed [463]3 years ago
7 0

Answer:

3%

Step-by-step explanation:

attashe74 [19]3 years ago
3 0

Answer:

3%

Step-by-step explanation:

I = Prt

    I = 1020

    P = 8500

    t = 4

1020 = (8500)(4)r

1020 = 34000r

r = 0.03

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Daniel [21]

Answer:

10

Step-by-step explanation:

-80 / -8 = 10

the negatives cancel each other out

3 0
3 years ago
Read 2 more answers
Exploring Systems of Linear Equations 2x +3y =8 and 3x+y= -2
butalik [34]

The solution of the linear equations will be ( -2, 4).

<h3>What is an equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

Given equations are:-

  • 2x +3y = 8 and 3x+y= -2

Solving the equations by elimination method:-

2x +3y = 8

3x+y= -2

Multiply the second equation by 3 and subtract from the first equation.

2x +3y = 8

-9x -3y = 6

----------------

      -7x = 14

         x = -2

Out of the value of x in any one equation, we will get the value of y.

3x+y= -2

3 ( -2) + y = -2

-6 + y = -2

y = 4

The graph of the equations is also attached with the answer below.

Therefore the solution of the linear equations will be ( -2, 4).

The complete question is given below:-

Exploring Systems of Linear Equations 2x +3y =8 and 3x+y= -2. Find the value of x and y and draw a graph for the system of linear equations.

To know more about equations follow

brainly.com/question/2972832

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3 0
2 years ago
What is the slope-intercept form of the linear equation 2x–8y=322x–8y=32 ?
gladu [14]
2x - 8y = 32
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y = (-2/-8)x - 32/8
y = 1/4x - 4 <== slope intercept form
5 0
4 years ago
Solve each equation. Showing your reasoning. X^2-6x-20=7
scoundrel [369]

Answer:

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Step-by-step explanation:

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3 years ago
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____ [38]

Answer:

\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}

Step-by-step explanation:

\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}

4 0
4 years ago
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