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natali 33 [55]
3 years ago
13

Consider an experiment whose sample space consists of a countably infinite number of points. Show that not all points can be equ

ally likely. Can all points have positive probability of occurring?
Mathematics
1 answer:
ella [17]3 years ago
3 0

Answer: if you have infinity points, which i will asume are the events, they cant have the same probability because then the probability will not be normalized, because in graph of prob vs variable, you will se infinite area under the curve if the probability is constant.

And yes, can all points have positive probability of occurring, but besides you medium value (the bell for example) you will see an asintotic decrease to the zero.

You might be interested in
can anyone help me with these? I'm having a lot of trouble and I'm extremely behind... I need to catch up badly!!! i have been a
TiliK225 [7]

Answer:

Step-by-step explanation:

5 and 6 are the same, so I will do one of those and you can use the example to do the other one.  

Slope-intercept form is y = mx + b.  If we have 2 points and nothing else, we can use those 2 points in the slope formula to find the slope (the m value in the equation) and then plug that in with either one of the points to get the equation.  The slope formula is:

m=\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

Using our points in question 5:  (2, 4) (5, 4)

m=\frac{4-4}{5-2} =\frac{0}{3}=0 So m = 0.  Now pick a point and use it in the equation along with the m value to solve for b.  I will use (2, 4):

4 = 0(2)+b and

4 = 0 + b so

b = 4.  

Now we have m = 0 and b = 4 so we fill in the equation with that info:

y = 0x + 4 or simplifying,

y = 4

For question 7 they want the line parallel to y = 3x + 6 that goes through (-10, 2.5).  For a line to be parallel to another line, their slopes have to be identical.  The slope in y = 3x + 6 is 3.  So the slope of the "new" line is going to be 3 as well.  Now we will use that slope and the given point to solve for b, just like in #5:

2.5 = 3(-10) + b and

2.5 = -30 + b so

b = 32.5

Now we will fill in:

y = 3x + 32.5

For question 8 they want the line perpendicular to y = -4x - 2 that goes through (-16, -11).  For a line to be perpendicular to another line, their slopes have to be opposite reciprocals.  Opposite meaning the sign is opposite (positive becomes negative and negative becomes positive), and reciprocal meaning the fraction is flipped upside down.  The slope in our line is -4.  That means that the perpendicular slope is positive 1/4.  Using that along with our point, we will again solve for b:

-11=\frac{1}{4}(-16)+b which simplifies to

-11 = -4 + b so

b = -7

Now we fill in:

y=\frac{1}{4}x-7

For question 8, in order to find the line parallel to the given line, you need to know the slope.  In the form it is currently in, we do not know the slope.  We need to put it into slope-intercept form to find the slope, then we will proceeed as above.  If

x + 4y = 6, then

4y = -x + 6 and, dividing by 4,

y=-\frac{1}{4}x+\frac{3}{2}

(The 3/2 is reduced from 6/4)

Now we can see the slope is -1/4.  We use that along with the point (-8, 5) to solve for b:

5=(-\frac{1}{4})(-8)+b which simplifies to

5 = 2 + b so

b = 3

Now we fill in, keeping in mind that lines are parallel when they have the exact same slope:

y=-\frac{1}{4}x+3

6 0
4 years ago
(6y + 3) minus (3y + 6) when y=7
never [62]

Answer:

y

Step-by-step explanation:

((((2•3y3) -  22y2) -  3y) -  —) -  2

                               y    

STEP

4

:

Rewriting the whole as an Equivalent Fraction

4.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  y  as the denominator :

                      6y3 - 4y2 - 3y     (6y3 - 4y2 - 3y) • y

    6y3 - 4y2 - 3y =  ——————————————  =  ————————————————————

                            1                     y          

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

5

:

Pulling out like terms

5.1     Pull out like factors :

  6y3 - 4y2 - 3y  =   y • (6y2 - 4y - 3)

Trying to factor by splitting the middle term

5.2     Factoring  6y2 - 4y - 3

The first term is,  6y2  its coefficient is  6 .

The middle term is,  -4y  its coefficient is  -4 .

The last term, "the constant", is  -3

Step-1 : Multiply the coefficient of the first term by the constant   6 • -3 = -18

Step-2 : Find two factors of  -18  whose sum equals the coefficient of the middle term, which is   -4 .

     -18    +    1    =    -17

     -9    +    2    =    -7

     -6    +    3    =    -3

     -3    +    6    =    3

     -2    +    9    =    7

     -1    +    18    =    17

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Adding fractions that have a common denominator :

5.3       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

y • (6y2-4y-3) • y - (6)     6y4 - 4y3 - 3y2 - 6

————————————————————————  =  ———————————————————

           y                          y        

Equation at the end of step

5

:

 (6y4 - 4y3 - 3y2 - 6)    

 ————————————————————— -  2

           y              

STEP

6

:

Rewriting the whole as an Equivalent Fraction :

6.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  y  as the denominator :

        2     2 • y

   2 =  —  =  —————

        1       y  

Checking for a perfect cube :

6.2    6y4 - 4y3 - 3y2 - 6  is not a perfect cube

Trying to factor by pulling out :

6.3      Factoring:  6y4 - 4y3 - 3y2 - 6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -3y2 - 6

Group 2:  6y4 - 4y3

Pull out from each group separately :

Group 1:   (y2 + 2) • (-3)

Group 2:   (3y - 2) • (2y3)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

6.4    Find roots (zeroes) of :       F(y) = 6y4 - 4y3 - 3y2 - 6

Polynomial Roots Calculator is a set of methods aimed at finding values of  y  for which   F(y)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  y  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  6  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1,2 ,3 ,6

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        1.00    

     -1       2        -0.50        -5.88    

     -1       3        -0.33        -6.11    

     -1       6        -0.17        -6.06    

     -2       1        -2.00        110.00    

Note - For tidiness, printing of 13 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Adding fractions that have a common denominator :

6.5       Adding up the two equivalent fractions

(6y4-4y3-3y2-6) - (2 • y)      6y4 - 4y3 - 3y2 - 2y - 6

—————————————————————————  =  ————————————————————————

            y                            y            

Polynomial Roots Calculator :

6.6    Find roots (zeroes) of :       F(y) = 6y4 - 4y3 - 3y2 - 2y - 6

    See theory in step 6.4

In this case, the Leading Coefficient is  6  and the Trailing Constant is  -6.

The factor(s) are:

of the Leading Coefficient :  1,2 ,3 ,6

of the Trailing Constant :  1 ,2 ,3 ,6

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -4.88    

     -1       3        -0.33        -5.44    

     -1       6        -0.17        -5.73    

     -2       1        -2.00        114.00    

Note - For tidiness, printing of 13 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Final result :

 6y4 - 4y3 - 3y2 - 2y - 6

 ————————————————————————

            y            

4 0
3 years ago
Read 2 more answers
Please help another question
butalik [34]

Answer is D) Y. It's matching with the results given

7 0
3 years ago
Mike had 119 dollars to spend on 6 books. after buying them he had 11 dollars. how much did each book cost ?
deff fn [24]
18 $ Hope I helped
This is how I came to the result..
119-11= 108
108 : 6 = 18 $
8 0
3 years ago
If salt (5.99 × 10–6 mol) is dissolved in 1.50 × 10–2 l of water, which expression can be used to find the molarity of the resul
kolezko [41]

The molarity of the resulting solution is 3.99 × 10⁻⁴ M. The correct option is the third option 3.99 × 10⁻⁴ M

<h3>Molarity of a solution</h3>

From the question, we are to determine the molarity of the resulting solution

From the given information,

Number of moles = 5.99 × 10⁻⁶ mol

Volume = 1.50 × 10⁻² L

Using the formula,

Molarity = Number moles / Volume

∴ Molarity = (5.99 × 10⁻⁶) / (1.50 × 10⁻²)
Molarity = 3.99 × 10⁻⁴ M

Hence, the molarity of the resulting solution is 3.99 × 10⁻⁴ M. The correct option is the third option 3.99 × 10⁻⁴ M

Learn more on Calculating molarity here: brainly.com/question/23051191

#SPJ1

5 0
2 years ago
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