Answer:
Step-by-step explanation:
We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.
First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.
Hence, we will have the three factors:
Where <em>a</em> is the leading coefficient.
Expand and simplify the second and third factors:
Hence:
Since f(-1) = 30:
In conclusion, third degree polynomial function is:
It is but it needs to be rearranged to x^2-2x+30
Answer:
(3,-2)
Step-by-step explanation:
Got it right!!
Answer:
x=4
Step-by-step explanation:
6^x = 1296
Take the log base 6 on each side
log6(6^x) = log6(1296)
Rewrite 1296 as 6^4
x = log 6(6^4)
We know that log( a^b) = b log (a)
x = 4 log6(6)
We know that loga(a) =1
x = 4 *a
x =4
8.
2 terms on left side, 3 on right side
9.
All variables count as coefficients, so they’d be 8m, k, and -16k
10.
The constants are just numbers on their own, or without a variable next to it. Here it’d be 10 and -4
