Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Slope is rise/run
to find it we do (y1-y2)/(x1-x2)
y1 means the 1st y and y2 means the second y
in (x,y) form
y1=4
y2=4
x1=10
x2=7
(4-4)/(10-7)=0/3=0
slope is 0
Answer: 12 boys: 13 Girls
Step-by-step explanation: Nothing much really.
Answer:
ask to your teachers and you will be finish the work
