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3 years ago

WILL MARK THE BRAINLIEST!! What are the amplitude, period, phase shift, and midline of f(x) = 2 sin(x + π) − 4?

Mathematics

1 answer:

xxMikexx [17]3 years ago

3 0

Answer:

Step-by-step explanation:

Amplitude is twice the coefficent of the sine function. In this case, $2*2=4$

Period is $2\pi$ divided by the coefficent of x, in this case, $\frac {2\pi} 1 =2\pi$

Phase shift, is how much you sum or subctract from x inside the sine, in this case $\pi$ .

Midline you get by hiding the sine and reading what's left, in this case, -4.

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A veterinarian wants to know if pit bulls or golden retrievers have a higher incidence of tooth decay at the age of three. The v

BigorU [14]

Answer: B) [-0.0332,0.1332]

Step-by-step explanation: <u>Confidence</u> <u>Interval</u> is an interval where we can be a percentage sure the true mean is.

The confidence interval for a difference in population proportion is calculated following these steps:

First, let's find population proportion for each population:

$p_{1}=\frac{30}{120}=0.25$

$p_{2}=\frac{32}{160}=0.2$

Second, calculate standard deviation for each proportion:

$\sigma_{1}=\sqrt{\frac{0.25(0.75)}{120} } = 0.0395$

$\sigma_{2}=\sqrt{\frac{0.2(0.8)}{160} } = 0.0316$

Now, we calculate standard error for difference:

$SE=\sqrt{\sigma_{1}^{2}+\sigma_{2}^{2}}$

$SE=\sqrt{0.0395^{2}+0.0316^{2}}$

SE = 0.0505

The z-score for a 90% CI is 1.645.

Then, confidence interval is

$p_{1}-p_{2}$ ± z-score.SE

$0.25-0.2$ ± $1.645(0.0505)$

0.05 ± 0.0831

The limits of this interval are:

inferior: 0.05 - 0.0831 = $-0.0332$

superior: 0.05 + 0.0831 = 0.1332

The 90% confidence interval for the difference in the population proportion of pit pulls and golden retrievers is $[-0.0332,0.1332]$ .

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3 years ago

Is the answer 4? I’m not sure if it’s right

kkurt [141]

Answer:

yes im pretty sure correct me if im wrong. Good luck!!!!!

Step-by-step explanation:

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3 years ago

Un depósito se llena de agua a diario para dar de beber a los animales de una granja. Según requerimiento se sacaron 3/8 del agu

Nostrana [21]

Answer:

5/24

Step-by-step explanation:

The question in English is

A tank is filled with water daily to give water to the animals on a farm. As required, 3/8 of the water was taken from the tank to give to the horses and 1/3 of what was left in the tank was given to the pigs. The remainder of the tank was distributed in two equal amounts to give water to the birds and pets. What is the fraction of the water that pets receive to drink?

1) 3/8 of the water was taken from the tank to give to the horses

At this point in the tank there are 1-3/8=5/8 of the water of the tank

2) 1/3 of what was left in the tank was given to the pigs

At this point in the tank there are

(1-1/3)*5/8

(2/3)(5/8)=10/24 of the water of the tank

3) The remainder of the tank was distributed in two equal amounts to give water to the birds and pets

The remainder is equal to 10/24

divided by 2

(10/24)/2=10/48

4) The fraction of the water that pets receive to drink is 10/48

simplify

10/48=5/24

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3 years ago