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oee [108]
3 years ago
5

Josie is creating 5 music playlists for her dance classes. She will use a total of 60 songs. Each playlist will have 7 older son

gs and the same number of newer songs.
Part A

Create an equation that can be used to determine the number of newer songs, n, Josie will have on each playlist.

Enter your equation in the box.
Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer: 60=5(7+x)

X= 5

Step-by-step explanation:

60 is the total amount of songs so it’s going to be divided into 5 different playlists. And those playlists are going to have 7 older songs plus the amount of new songs.

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Given triangle ABC with sides AB = 3x + 4 , BC = 2x + 5 , and AC = 4x , determine the values of x such that triangle ABC exists
Jlenok [28]

Answer:

  x > 1/5

Step-by-step explanation:

All of these three triangle inequalities must be satisfied:

  AB +BC > AC

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Taking these one at a time, we have ...

  AB +BC > AC

  3x +4 + 2x +5 > 4x

  x +9 > 0 . . . . . subtract 4x

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  2x +5 + 4x > 3x +4

  3x > -1 . . . . . . subtract 3x+5

  x > -1/3 . . . . . divide by 3

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  CA + AB > CB

  4x + 3x +4 > 2x +5

  5x > 1 . . . . . . subtract 2x+4

  x > 1/5

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The only values of x that satisfy all of these inequalities are those such that ...

  x > 1/5

8 0
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Gravitational force acts on all object in proportion to their masses. Why then, a heavy object does not fall faster than a light
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Four times a number, minus 9, is equal to three times the number, plus 6
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Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
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