I hope this helps you
[20x^2/4x^2y]+[4xy^2/4x^2y]-[8y^2/4x^2y]
[5/y]+[y]-[4y/x^2]
2 becuae......................................................................................................you have 5/10
1. 864 mm^3
2.1640 cm^3
3. 4.0 cm
4. 150pi ft^3
I'm sorry but what was the question? Uploading the Image would be helpful.
Answer:
D
Step-by-step explanation:
There is no data set so there is no data to find the mean of.
