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oee [108]
3 years ago
15

TIMED TEST??????!?!?!?!?!?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
3 0

Answer:

Its bad to cheat on a test my dude

Step-by-step explanation:

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Alisons mom was baking cupcakes for the school's bake sale.Each of her cupcake pans can hold up to 8 cupcakes.If she has 9 cupca
Ivan
The answer is 72!!


- hope this helped!!!
8 0
3 years ago
Kenya is solving the equation 5 3/4 - 1/6x = 4 1/2. She gets to 1 1/4 = 1/6x. Is this a valid way to solve the equation? answer
Alona [7]

Answer:

15/2

Step-by-step explanation:

5 3/4 - 1/6x = 4 1/2

move the variable to it's own side.

5 3/4 - 4 1/2 = 1/6x

change the subtracting side to have common denominators

5 3/4 - 4 2/4 = 1/6x

1 1/4 = 1/6 x

divide both sides by 1/6, same thing as multiplying both sides by 6 (reciprocal)

30/4 = x

reduce: 15/2 = x

8 0
3 years ago
If a man earns 90cents every 3 minutes and he works for a day shift of 5hours how much will he earn in that time?
zavuch27 [327]

Answer:

It is 9000 cents or $90 total for 5 hours

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Relate-to-a-Simpler-Problem
Alex73 [517]

Answer:

1. 128 pages.

2. (y - x) + 1

3. 6 pages.

4. Helps to formulate the expression for the number of pages read.

Step-by-step explanation:

1. George will read pages 385 through 512 in his karate history book. And we are asked to find the number of pages that he will read.

The required number of pages that George read will be = (512 - 385) + 1 = 128 pages.

2. If he read from page number x through page number y then the general rule of finding the number pages that he read will be = (y - x) + 1

3. If x = 500 and y = 505, then the number of pages read is = (505 - 500) + 1 = 6 pages.

Again, if x = 5 and y = 29, then again the number of pages read is = (29 - 5) + 1 = 25 pages.

4. The rule just formulates the expression for the number of pages read and it eases the calculation for the number of pages read. (Answer)

7 0
3 years ago
Solve the system of equations.
emmainna [20.7K]

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Explanation:</h2>

We have the following system of three linear equations:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\5~ x&+~~8~ y&+~~~~ z&~=~4\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Let's use elimination method in order to get the solution of this system of equation, so let's solve this step by step.

Step 1: Multiply first equation by -5/2 and add the result to the second equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Step 2: Multiply first equation by −2 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&-~~~3~ y&-~~~62~ z&~=~-6\end{array}

Step 3: Multiply second equation by −32 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&&+~~\frac{ 113 }{ 2 }~ z&~=~\frac{ 21 }{ 2 }\end{array}

Step 4: solve for z.

\begin{aligned}       \frac{ 113 }{ 2 } ~ z & = \frac{ 21 }{ 2 } \\      z & = \frac{ 21 }{ 113 }       \end{aligned}

Step 5: solve for y.

\begin{aligned}-2y-79z &= -11\\-2y-79\cdot \frac{ 21 }{ 113 } &= -11\\y &= -\frac{ 208 }{ 113 } \end{aligned}

Step 6: solve for x by substituting y=-\frac{208}{113} and z = \frac{21}{113} into the first equation:

2x+4(-\frac{208}{113})+32(\frac{21}{113})=6 \\ \\ 2x-\frac{832}{113}+\frac{672}{113}=6 \\ \\ 2x=6+\frac{832}{113}-\frac{672}{113} \\ \\ 2x=\frac{838}{113} \\ \\ x=\frac{319}{113}

Finally:

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Learn more:</h2>

Solving System of Equations: brainly.com/question/13121177

#LearnWithBrainly

7 0
3 years ago
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