Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
Could you do 31 add 31 which would also be 31 multiplyed by 2
hope this helps
Answer:
Step-by-step explanation:
8,6,2, and 1
(2^6 / 8) * 1 = (64/8) * 1 = 8 * 1 = 8
The answer is a.0
Concentric means these circles would have the same center, thus, the smaller circle must be inside the bigger circle. Any tangent line to the smaller circle wont be a tangent line to the bigger circle, since that tangent line would intersect at the bigger circle at 2 points. Any tangent line to the big circle will not touch the small circle... so the answer would be 0.
Answer:
h=13z-30+ 27/z
Step-by-step explanation: