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saul85 [17]
3 years ago
8

Write the function y-3=2/3(x-4) in the equivalent form most appropriate for identifying the slope and - intercept of the functio

n.
Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

Slope = 2/3

intercept= 1/3

Step-by-step explanation:

The standard form of equation of a line in slope intercept form is expressed as;

y = mx+b

m is the slope

b is the y-intercept

Given the expression

y-3=2/3(x-4)

Cross multiply

3(y-3)=2(x-4)

Expand

3y - 9 = 2x - 8

3y - 2x = -8 + 9

3y - 2x = 1

3y = 2x+1

Divide through by 4

y = 2/3 x  + 1/3

Comparing

mx = 2/3 x

m = 2/3

b = 1/3

Hence the slope of the function is 2/3 and the intercept is 1/3

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Plz help me I am timed plz
lys-0071 [83]

Answer:

it's D

Step-by-step explanation:

step 1 : add all the numbers

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7 0
3 years ago
Read 2 more answers
DeLuxe Cinema has a summer bundle: 3 tickets for $36.75. Regular price for 1 ticket is $11.75. If you need 3 tickets, which is t
Marianna [84]

Answer:

buying 3 of the regular price tickets

Step-by-step explanation:

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5 0
2 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
3 years ago
Convert to Scientific Notation.
tino4ka555 [31]

Answer:

7.6 over 0.0000054

8 0
2 years ago
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