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Mashcka [7]
3 years ago
8

42.54 degrees is the same as 42 degrees______ '42"

Mathematics
1 answer:
pav-90 [236]3 years ago
3 0
The answer is 24" hope this helps.
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Number 4 please I need help please I need help please help me
kotykmax [81]

Answer:

The perimeter is 112 m

Step-by-step explanation:

The perimeter is the sum of all the edges

26+ 12 + 18 +? + ?+ 30

The two question marks add to 26 so replace them with 26

26+ 12 + 18 +26+ 30

112

The perimeter is 112 m

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4 years ago
Multiply.<br><br> (4x+2)(3x+3)
Wewaii [24]

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4 0
3 years ago
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BRAINLIEST if correct<br><br> 2.0
Mandarinka [93]

Answer:

(I labeled them as letters) your answer is going to be a and e

Step-by-step explanation:

The maximum is the highest number they are going and north has the higher number in the scale. The lower quartile is lower in the scale for north than south.

8 0
3 years ago
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What is the perimeter of the polygon in the diagram?
rusak2 [61]

Answer:

The correct answer is:

<em><u>D.</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>√</u></em><em><u>a</u></em><em><u>²</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em><em><u>²</u></em>

3 0
3 years ago
Please answer the question in the photo, thanks!
belka [17]

Answer:

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right )

We rearrange the fractions as improper  fractions for easier division as follows;

2\dfrac{1}{3}  = \dfrac{7}{3}

-3\dfrac{2}{3} = -\dfrac{11}{3}

Therefore, we have;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

4 0
3 years ago
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