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igor_vitrenko [27]
3 years ago
11

Hannah either walks or cycles to school. The probability that she walks to school is 0.75. If she walks, the probability that sh

e is late is 0.6. If she cycles, the probability that she is late is 0.2. Work out the probability that on any one day Hannah will not be late for school

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer:

0.17

Step-by-step explanation:

im not really sure but that closest as 0.75+0.6+0.2=0.83 and 1.00-0.83=0.17

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Team A and team B play a series. The first team to win three games wins the series. Each team is equally likely to win each game
andrezito [222]

Answer:

Probability is \frac{1}{4}

Step-by-step explanation:

This problem can be easily done tree diagram.

Few things keep in mind :

  • From starting of match three victories of A.
  • Less then or equal to two victories of B.
  • In each matches there are two possibilities either favourable for A or B.

First case if A wins first match

  1.       two victories of B then two of A
  2.       victory of B then A then B then A
  3.       victory of B then A then A

Second case if B wins first match(favorable)

  1.      victory of two B then three A

So total cases are 4 and favorable is one

  probability=\frac{1}{4}

[Tree diagram is in attachment]

7 0
4 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%281-0.08%29%5E%7B%5Cfrac%7B1%7D%7B12%7D%20%7D%20%5E%7B%2812t%29%7D" id="TexFormula
oksano4ka [1.4K]

Answer:

See Below.

Step-by-step explanation:

We have:

\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}

First, we can subtract within the parentheses:

f(x)=(0.92)^{\frac{1}{12}(12t)}

By the properties of exponents:

f(x)=((0.92)^\frac{1}{12})^{12t}

Approximate. Use a calculator:

f(x)\approx (0.993)^{12t}

Notes:

0.993 is only an approximation, hence the approximately equal sign.

I'm not given the context of the problem, but it's simpler to just simplify in the exponent like so (the fractions cancel):

\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}=(0.92)^t

Full Problem:

The value of Sara's car decreases at a rate of 8% per year.

We will use the exponential decay formula with a set time, given by:

f(x)=a(r)^{x/d}

Where a is the initial value, r is the rate, x is the time that has passed (dependent on d), and d is the amount of time for one decrease.

For this problem, we can ignore the initial value.

And since the value decreases at a rate of 8% per year, r = 0.92 (we acquire this from 1 - 0.08).

Part 1) Per Month:

Since it decreases per month, d = 12.

f(x)=(0.92)^{x/12}

Approximate:

f(x)=((0.92)^{1/12})^x\approx(.993)^x

In this case, x is measured in months.

Part 2) Per Week:

Since it decreases per week, d = 52.

f(x)=(0.92)^{x/52}

Approximate:

f(x)=((0.92)^1/52)^x\approx (.998)^x

In this case, x is measured in weeks.

Part 3) Per Day:

So, d = 365.

f(x)=(0.92)^{x/365}

Simplify:

f(x)=((0.92)^{1/365})^x\approx(.999)^x

In this case, x is measured in days.

Part 4)

So, as d increases, our r increases as well.

Therefore, the smaller the time interval (from months to weeks to days), the higher our rate of decrease is.

8 0
3 years ago
I’m confused on this one
andrew-mc [135]

First we need to know the point slope form. It is y - y1 = m(x - x1). In the y1 and x1 spots, you just plug in any coordinate on the line.

m would be the slope which we already know as 5/3.

We are given the coordinate point (0,3) as a point on the line. This is also what we are going to plug into the equation. 0 will be x1 and 3 will be y1.

Our equation should then look like after plugged in as....

y - 3 = 5/3(x)

x is by itself because subtracting or adding by 0 yield the original number.

6 0
3 years ago
You have $1000 to invest in two different accounts. In order to save the money you need for college, you need to average 6.6 per
Aleks04 [339]

Answer:

a) $500 + $525 = $ 1,025

b) $420 + $642 = $ 1,062

c) $210 + $856 =  $ 1,066

d) $840 + $214 =  $ 1,056

Step-by-step explanation:

Compound Interest Equation

A = P(1 + r/n)^nt

Where:

A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

R = Annual Nominal Interest Rate in percent

r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

n = number of compounding periods per unit t; at the END of each period

Compound Interest Formulas and Calculations:

Calculate Accrued Amount (Principal + Interest)

A = P(1 + r/n)^nt

Calculate Principal Amount, solve for P

P = A / (1 + r/n)^nt

Calculate rate of interest in decimal, solve for r

r = n[(A/P)^1/nt - 1]

Calculate rate of interest in percent

R = r * 100

Calculate time, solve for t

t = ln(A/P) / n[ln(1 + r/n)] = [ ln(A) - ln(P) ] / n[ln(1 + r/n)]

4 0
3 years ago
Write L if it is Likely to happen and Write U if it is unlikely to happen. Topic is probability
erica [24]

Answer:

1h b+h boi gate

Step-by-step explanation:

4 0
3 years ago
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