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3 years ago

Solve the system of equations y =2x -9 y = x - 4

Mathematics

1 answer:

Anit [1.1K]3 years ago

8 0

Y=2x-9
y=x-4

x-4=2x-9

+9 each side=

x+5=2x

-x each side=

5=x

flip for the final answer of x=5

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On October 1, Bandor Company sold land (that cost $30,000) on credit for $35,000. The buyer issued an 8%, 12-month note for this

Nadusha1986 [10]

Answer:

Check the explanation

Step-by-step explanation:

Journal entries are as follows:-

Date Account Titles Debit Credit

Oct-01. 8% Note Receivable $35,000.00

Land $30,000.00

Gain on sale $5,000.00

(Sale of Land)

Dec-31 Interest Receivable $700.00

Interest Revenue $700.00

(Interest revenue on Note for 3 mon. recognized)

($35,000 * 8% *3/12 = $700)

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3 years ago

Triangle XYZ is located at X (−2, 1), Y (−4, −3), and Z (0, −2). The triangle is then transformed using the rule (x−1, y+3) to f

Brrunno [24]

The given points are X (−2, 1), Y (−4, −3), and Z (0, −2)

By using the rule (x − 1, y + 3) the points then become:

X′ (− 2 − 1, 1 + 3), Y′ (− 4 − 1, − 3 + 3), and Z′ ( 0 −1, − 2 + 3)

X′ (− 3, 4), Y′ (− 5, 0), and Z′ (− 1, 1)

If the corresponding vertices of both triangles were connected with line segments then we should get exact congruent triangles with just x- and y-coordinates transformed or we can say that:

△XYZ=△X′Y′Z′

Answer: X′ (− 3, 4), Y′ (− 5, 0), and Z′ (− 1, 1)

8 0

3 years ago

Halp asap plssssssssssssssssss

sashaice [31]

Answer:

a. $-56c+30$

Step-by-step explanation:

$4c+10\left(3-6c\right)$

Expand:

$4c+10\times3-10\times6c$

$4c+30-60c$

$4c-60c+30$

$-56c+30$

6 0

4 years ago

Find an equation of the tangent line to the hyperbola x2 a2 − y2 b2 = 1 at the point (x0, y0).

nalin [4]

The equation of the tangent line is $y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

To find the tangent to the hyperbola $\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }$ at (x₀, y₀), we differentiate the equation implicitly to find the equation of the tangent at (x₀, y₀).

So, $\frac{d}{dx} (\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }) = \frac{d0}{dx}\\\frac{d}{dx} \frac{x^{2} }{a^{2} } - \frac{d}{dx}\frac{y^{2} }{b^{2} }= 0\\\frac{2x }{a^{2} } - \frac{dy}{dx}\frac{2y }{b^{2} } = 0\\\frac{2x }{a^{2} } = \frac{dy}{dx}\frac{2y }{b^{2} } \\\frac{dy}{dx} = \frac{b^{2}x }{a^{2}y }$

So, at (x₀, y₀)

$\frac{dy}{dx} = \frac{b^{2} x_{0} }{a^{2} y_{0} }$

So, the equation of the tangent line is gotten from the standard equation of a line in point-slope form

So, $\frac{y - y_{0} }{x - x_{0} } = \frac{b^{2} x_{0} }{a^{2} y_{0} } \\y - y_{0} = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) \\y = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) + y_{0} \\y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

So, the equation of the tangent line is $y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

Learn more about equation of tangent line here:

brainly.com/question/12561220

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3 years ago

Which statement is correct with respect to f(x) = -3|x − 1| + 12?

sertanlavr [38]

The answer should be D if not it is C

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3 years ago

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