58/2=29
29 is prime
prime factorization is 2 times 29
D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
umm you have to give us more info
Step-by-step explanation:
without info we can not properly answer the question
Answer:
The answer to your question is the first graph in the second line.
Step-by-step explanation:
First graph in the first line: it shows a positive graph that intercepts the y-axis in 5, then this graph is not the correct answer.
Second graph in the first line: it shows a negative graph, this option is incorrect, we look for a positive graph.
First graph in the second line: is correct because is a positive graph and intercpts the y-axis in 4.
Second graph in the second line: is incorrect although it is a positive graph, it intercepts the y-axis in 3.
