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Margarita [4]
3 years ago
15

In ΔDEF, the measure of ∠F=90°, the measure of ∠D=62°, and FD = 3.5 feet. Find the length of DE to the nearest tenth of a foot.

Mathematics
2 answers:
sp2606 [1]3 years ago
4 0

Answer:

7.5

Step-by-step explanation:

anastassius [24]3 years ago
3 0

Answer:

7.5 feet

Step-by-step explanation:

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Telephone plan consist of a monthly fee of $20 plus $.20 per minute for long distance calls made write an equation for the total
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C=20+0.20N

Step-by-step explanation:

Fixed monthly fee = $20

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Amount charged for N minutes for long distance calls =0.20N

Therefore, an equation for the total cost, C, when N minutes are used for long distance calls is C=20+0.20N

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Find the slope of the line that passses thruogh 1,5 and 10,9
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The following table shows the working populations, average salaries, and income tax rates of France and Ger
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Step-by-step explanation:

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
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Answer:

Part a) The area of the figure is \frac{9}{2}(4+\pi )\ cm^{2}

Part b) The perimeter of the figure is 3(2+2\sqrt{2}+ \pi)\ cm

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

AB=6\ cm, BC=6\ cm

The area of the half square ABC is equal to find the area of triangle ABC

so

A1=\frac{1}{2}*6*6=18\ cm^{2}

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

A2=\pi r^{2}/2

we have that

r=6/2=3\ cm

substitute

A2=\pi (3)^{2}/2

A2=(9/2) \pi\ cm^{2}

The area of the figure is equal to

18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

P=AB+AC+length\ CB

we have

AB=6\ cm

Applying Pythagoras theorem

AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm

Remember that

the circumference of a semicircle is equal to

C=\frac{1}{2}2\pi r=\pi r

r=6/2=3\ cm

C=\pi(3)

C=3 \pi\ cm

The perimeter of the figure is equal to

P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm

Simplify

P=3(2+2\sqrt{2}+ \pi)\ cm

5 0
3 years ago
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