Five thousand eight hundred nine-two people are going to a wedding. They can fit 80 people comfortably in each bus. How many bus
2 answers:
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Answer:
The sum of the two vectors is the vector <-0.5 , 4+3.5 >
Step-by-step explanation:
The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф
The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф
The vector is <b cos Ф , b sin Ф>
∵ The vector goes 7 units at an angle
- That means its magnitude is 7 and its direction is
∴ x = 7 cos( )
∴ y = 7 sin( )
∵ cos( ) =
∵ sin( ) =
- Substitute them in x and y
∴ x = (7)( )
∴ x = -3.5
∴ y = (7)( )
∴ y = 3.5
∴ The vector is <-3.5 , 3.5>
Now lets add the vectors by adding xs and ys components
∵ <3 , 4> + <-3.5 , 3.5 > = <3 + -3.5 , 4 + 3.5
>
∴ <3 , 4> + <-3.5 , 3.5> = <-0.5 , 4+3.5
>
∴ The sum of the two vectors is the vector <-0.5 , 4+3.5 >
I switched the x and y so it’s easier to see. The answer is (x-1)/(23).
In these questions, we need to follow the steps:
1 - solve for the trigonometric function
2 - Use the unit circle or a calculator to find which angles between 0 and 2π gives that results.
3 - Complete these angles with the complete round repetition, by adding
4 - these solutions are equal to the part inside the trigonometric function, so equalize the part inside with the expression and solve for <em>x</em> to get the solutions.
1 - To solve, we just use algebraic operations:
2 - From the unit circle, we can see that we will have one solution from the 2nd quadrant and one from the 4th quadrant:
The value for the angle that give positive
is known to be 30°, which is the same as π/6, so by symmetry, we can see that the angles that have a tangent of
Are:
3 - to consider all the solutions, we need to consider the possibility of more turn around the unit circle, so:
Since 5π/6 and 11π/6 are π radians apart, we can put them together into one expression:
4 - Now, we need to solve for <em>x</em>, because these solutions are for all the interior of the tangent function, so:
So, the solutions are:
