I put the ... because it just keeps on going. Just round it to 8.
Lets set the two numbers as 'a' and 'b'
Now let us set up some equations based on the information:
- sum of two numbers 49 --> a + b = 49
- difference of the two numbers is 15 --> a -b =15
Equations
a + b = 49 -- equation 1
a - b = 15 -- equation 2
Solve:
(equation 1) + (equation 2)
2a = 64
a = 32 -- equation 3
(equation 3)'s value of a into (equation 2)
32 - b = 15
b = 17
The products of 'a' and 'b' is 544
Hope that helps!
Answer:
V≈ 863.27 in³
Step-by-step explanation:
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
The standard form of a quadratic equation is ,
ax² + bx + c = 0.
And the formula to find the discriminant is b² - 4ac.
Here the first step is to change the given equation into standard form. So, add 1 to each sides of the equation. Therefore,
2x² – 9x + 2+1 = –1 + 1
2x² – 9x + 3 = 0
Next step is to compare the given equation with this equation to get the value of a, b and c.
After comparing the equations we will get a = 2, b = -9 and c = 3.
So, discriminant = b²- 4ac
=( -9)²-4 (2)(3)
= 81 - 24
= 57
So, discriminant of the given equation is 57.
57 is greater than 0 and square root of 57 will result real number.
So, the correct choice is C: The discriminant is greater than 0, so there are two real roots.
