Answer:
An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation. Example 1: Solve for x , 1x − 2+1x + 2=4(x − 2)(x + 2) .Set the equation to equal zero. (this ends up being √x+4−x+2=0 )
Plug this into the y= button on your TI-83/84 calculator.
Find the value of each of your solutions (go to 2nd->Calc->Value and enter your solution for x )
You should get zero as an answer for each of them.
Step-by-step explanation:
Extraneous solutions are not solutions at all. They arise from outside the problem, from the method of solution. They are extraneous because they are not solutions of the original problem. ... To tell if a "solution" is extraneous you need to go back to the original problem and check to see if it is actually a solution.
Answer:
If 67860÷13,then quotient =5220Answer
Answer:
P(seventh grade winner) = 3/8
Step-by-step explanation:
First, find the total number of ounces:
(28)(16) = 448 oz (16oz in a lb)
Then divide 448 by 8
448/8 = 56 days of food
Given that
attains a maximum at
, it follows that
at that same point. So integrating once gives
and so the first derivative is
.
Integrating again, you get
You know that this curve passes through the point (2, -1), which means when
, you have
:
and so
