Answer:AC = 20
BK = 9.6
Step-by-step explanation:
AC is found using the Pythagorean theorem in the usual way:
AC² = AB² + BC²
AC² = 12² + 16² = 144 +256 = 400
AC = √400
AC = 20
You may recognize this is a 3-4-5 triangle scaled by a factor of 4.
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Then BK is found using similar triangles. All of the triangles in the figure are similar*, so ...
long side / hypotenuse = BC/AC = BK/AB
BK = AB(BC/AC) = 12(16/20) = 12×0.8
BK = 9.6
-7/2 and -1/2 (there both fractions)
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3.
Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then
A(Y) = 2A(X)
[T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3
But [T(X)]^2 = [A(X)]^3
Thus [T(Y)]^2 = 2^3[T(X)]^2
[T(Y)]^2 / [T(X)]^2 = 2^3
T(Y) / T(X) = 2^3/2
Therefore, the orbital period increased by a factor of 2^3/2
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9514 1404 393
Answer:
45, 56, 67
Step-by-step explanation:
Terms of an arithmetic sequence have a common difference. That is, the next term is found by adding that difference to the previous term.
Here, the difference is 12 -1 = 11, so each term is 11 more that the previous one. The next terms are found by repeatedly adding 11.
34 + 11 = 45
45 + 11 = 56
56 + 11 = 67
The next three terms are 45, 56, 67.
Answer: A
Step-by-step explanation:
HxWxL equals 4/60. 4/60 simplified is 1/15.