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zepelin [54]
2 years ago
10

01010101010101010100101010100100101010101010010101101001010101101001010100101010101010100000000010101010101010010101010101010101

011001001101010101010010101001010100101010110011010010101010101010101011001101010110101010101010110011001010101010101010010110010101010100101010010101010101010101010101010101001010101010010101010110: BINARY CODEEEEEEEEEEEEEEE
number 5 might be kinda of hard too read soory

Mathematics
1 answer:
Xelga [282]2 years ago
5 0

Answer:

1. first one

2. there are no solutions that i see

Step-by-step explanation:

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In an honors math class of 25 students, 15 are boys and 10 are girls. On the final exam, 6 boys and 3 girls received a grade of
postnew [5]

Answer:

Step-by-step explanation:

b=boy

a= a on the exam

b=15

b∩a=6

b'∩a=3

b'∪a'=?

b'∪a'= b'+a'-b'∩a'

a= b∩a+b'∩a (law of total probability) = 9

a'= 25-9 = 16

b'= 25-15= 10

16+10-7=19

19/25= .76

7 0
3 years ago
What is the area of the rectangle? Round to the nearest square inch.
Mademuasel [1]
Asking the Math Gods...

A=W*L

9*3=27in^2
9*5=45in^2

3 0
3 years ago
How do you do this ? Please step by step explanation due tom
inna [77]

Answer: C im pretty sure

Step-by-step explanation:

Use this link it explains it pretty well

https://www.calculatorsoup.com/calculators/math/mixednumbers.php

Just copy and paste the link

6 0
3 years ago
Si en 11 cajas de chocolates hay 220 chocolates en total. Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.
pochemuha

Answer:

Habrá 100 chocolates en total en 5 cajas de chocolates.

Step-by-step explanation:

Esta pregunta es resolvida usando proporciones, con lo uso de regla de tres .

11 cajas, 220 chocolates:

Entonces:

\frac{220}{11} = 20

20 chocolates por caja.

Calcula cuántos chocolates habrá en total en 5 cajas de chocolates.

20 chocolates por caja, entonces:

5*20 = 100

Habrá 100 chocolates en total en 5 cajas de chocolates.

6 0
2 years ago
How would you do this question?
diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0
3 years ago
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