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LenKa [72]
3 years ago
11

In order to meet ADA (Americans with Disabilities Act) requirements, a wheelchair ramp must have an angle of elevation of no mor

e than 4.8∘. A builder needs to install a ramp to reach a door that is 1.5 feet off the ground. What angle of elevation will this ramp have?
Is 25 feet long enough for the straight line distance of the ramp to meet the requirements? What angle of elevation will this ramp have?

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0

Check the picture below.

make sure your calculator is in Degree mode.

does it meet the requirements?  well, 3.43 < 4.8.

lukranit [14]3 years ago
6 0

Answer:

a. The angle of elevation should be less than 4.8 ° since that is the maximum standard.

b. The angle of elevation is 3.4°.  25 ft is long enough for the straight line distance of the ramp to meet the requirement .  

Step-by-step explanation:

The standard required angle of elevation must have an angle of elevation not more than 4.8°.

A builder needs to install the ramp to reach a door that is 1.5 ft off the ground . The angle of elevation can be calculated as follows :

The illustration forms a right angle triangle .

opposite side = 1.5 ft

adjacent side = a

The angle of elevation should be less than 4.8 ° since that is the maximum standard.

Is 25 feet long enough for the straight line distance of the ramp to meet the requirements? What angle of elevation will this ramp have?

opposite side = 1.5 ft

adjacent side = 25 ft

∅ = angle of elevation

Using SOHCAHTOA principle

tan ∅ = 1.5/25

∅ =  arctan 0.06

∅ = 3.433630362

The angle of elevation is 3.4°.  

25 ft is long enough for the straight line distance of the ramp to meet the requirement .  

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Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

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Svetach [21]

Answer:

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Step-by-step explanation:

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m_a_m_a [10]

Answer:                         t=33

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