This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
Answer:
0% probability that a customer will be exactly 7.50 minutes in the record store.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
The probability of finding a value between c and d is:
The probability of finding a value above x is:
The uniform distribution is a continuous distribution, which means that the probability of an exact outcome is zero.
Uniformly distributed between 3 and 12 minutes.
This means that 
What is the probability that a customer will be exactly 7.50 minutes in the record store?
Continuous distribution, so:
0% probability that a customer will be exactly 7.50 minutes in the record store.
Answer:
4x-20
Step-by-step explanation:
Answer:
The answer is 7600 because in order to reach negative coordinates you have to travel the length to 0 then down the scale to -1, -2, -3, and so on and vice versa to get to positive coordinates.