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omeli [17]
3 years ago
15

What is the ansar to 2+2 please I’m 3 and I hove preK hamewark

Mathematics
2 answers:
puteri [66]3 years ago
7 0
4 is the answer little Johnny
Svet_ta [14]3 years ago
6 0

Answer:

4

Step-by-step explanation:

2+2=4

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“Write an equation in standard form of the horizontal line that goes through (-7, 10)”
OlgaM077 [116]

Answer:

Step-by-step explanation:

A horizontal line is only concerned with the y value. The equation is y = 10 because that is the point that the line must go through.

The x value does not matter as long as the y value is given as 10. The domain is any real value. The range is 10

6 0
3 years ago
I need answer for this question
otez555 [7]
Take the cube root of 216. You will get 6
5 0
3 years ago
Read 2 more answers
5. A deck should have a perimeter of 90 feet and a minimum area
Ket [755]

Answer:

The minimum value of the width is 15 ft and the maximum value of the width is 30 ft

Step-by-step explanation:

Let

x -----> the length of the deck

y ----> the width of the deck

we know that

The perimeter of the deck is equal to

P=2(x+y)

P=90\ ft

so

90=2(x+y)

45=(x+y)

x=45-y -----> equation A

The area is equal to

xy\geq 450 -----> inequality B  

(45-y)y\geq 450\\ \\-y^{2} +45y-450\geq 0

Solve the quadratic equation by graphing

The possible width of the deck are the values of y in the interval

[15,30]

All real numbers greater than or equal to 15 ft and less than or equal to 30 ft

see the attached figure

The minimum value of the width is 15 ft and the maximum value of the width is 30 ft

7 0
3 years ago
You are planning a new production floor. You will need space for eight manufacturing processes and six stockpiles. Each takes 16
mina [271]

Answer:

Total space needed is 3136 square feet.

Step-by-step explanation:

We are given the following in the question:

Space required for eight manufacturing processes and six stockpiles.

Each takes 160 square feet.

Space required for 8 process =

=8\times 160\\=1280\text{ square feet}

Space required for 6 stockpiles =

=6\times 160\\=960\text{ square feet}

Total space =

=1280 + 960\\=2240\text{ square feet}

Open space required = 40%

=\dfrac{40}{100}\times 2240\\\\=896\text{ square feet}

Total space required =

=2240 + 896\\=3136\text{ square feet}

Thus, total space needed is 3136 square feet.

4 0
3 years ago
Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?
Sveta_85 [38]

Complete Question:

Is the value of the fraction 7−2y/6 greater than the value of the fraction 3y−7/12 ?  For what values?(Make sure to use an inequality)

Answer:

y < 3

Step-by-step explanation:

The given two fractions are:

\frac{7-2y}{6} and \frac{3y-7}{12}

We have to tell for which range of values is the value of first fraction larger than the second fraction. This can be done by setting up an inequality as shown:

\frac{7-2y}{6} >\frac{3y-7}{12}

The range of y which will satisfy this inequality will result in first fraction of larger value as compared to the second fraction.

Multiplying both sides of inequality by 12, we get:

12 \times \frac{7-2y}{6} > 12 \times \frac{3y-7}{12} \\\\  2(7-2y)>3y-7\\\\ 14-4y>3y-7\\\\ 14+7>3y+4y\\\\ 21>7y\\\\ 3>y\\\\ y

This means, for y lesser than 3, the value of first fraction is larger than the second one.

3 0
3 years ago
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