Answer: The loser's card shows 6.
Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
4 3
5 3
6 2
6 3
9 2
12 1
15 1
18 1
Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.
1 12
1 15
1 18
2 6
2 9
3 4
3 5
3 6
6 2
6 3
Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.
2 6
3 6
Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
Answer:
Choose a point with a negative x coordinate and a positive y coordinate.
Step-by-step explanation:
The quadrants are labeled counter clockwise 1, 2, 3, and 4.
Quadrant I - has x and y coordinate both positive.
Quadrant 2 - has x coordinate negative and y coordinates positive.
Quadrant 3 - has x and y coordinates both negative.
Quadrant 4 - has x coordinates positive and y coordinates negative.
Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).
