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const2013 [10]
3 years ago
11

Solve 2/3x-1/5>1. x>

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

Answer:

x> 9/5

Step-by-step explanation:

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Please answer this if you know it ( you only have to answer the problem it’s asking)
neonofarm [45]

9514 1404 393

Answer:

  vertex: (-2, 4)

Step-by-step explanation:

Use your regression calculator to find the parameters of the quadratic model.

The vertex form equation is ...

  y = -3(x +2)^2 +4

so the vertex is (-2, 4).

__

The standard form equation is the expansion of the above:

  y = -3x^2 -12x -8

4 0
3 years ago
What are the first six nonzero multiples of 3
Mamont248 [21]
3,6,9,12,15 thats what i think. hope it helps
5 0
4 years ago
Please help, I’ll mark your answer as brainliest.
Brrunno [24]

Answers:

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\

========================================================

Work shown for part 1

f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\

----------------------------------

Work shown for part 2

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\

6 0
2 years ago
23b=161 show work and step by step please
dalvyx [7]
Answer:  b=161/23
               b=7
7 0
3 years ago
When somebody loved me
-Dominant- [34]

Answer:

That is really sweet. AWWWWWWWWWW

Step-by-step explanation:

Everyone is loved including you.

6 0
4 years ago
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