To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
How can you use a bar diagram to check the accuracy of the solution to a ratio or rate problem<span>? ... To see which bar is higher... the higher the bar the soloution if the ratio ... If the ratio of problems she finished to problems she still had left was 8 : 1, how many homework problems did she have total?</span>
20/10 as a mixed number:
20 ÷ 10 = 2.
10 goes into 20 two times. So 20/10 as a mixed number is a whole number: 2.
20/10 = 2
Given:
A box-and-whisker plot of data set.
To find:
The percentage of the data values that are greater than 80.
Solution:
From the given box-and-whisker plot, it is clear that:
Minimum value = 8
First quartile = 60
Median = 68
Third quartile = 80
Maximum value = 92
We know that the 25% the data value are greater than or equal to third quartile because the third quartile divides the data in 75% to 25% and 80 is the third quartile.
Therefore, about 25% of the data values that are greater than 80.
Answer:
3
Step-by-step explanation:
5(x-1)-2
5(2-1)-2
5×1-2
5-2
3
Hope this helps you :)
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