Aerobic or anaerobic atp exchange <span />
Answer:
7 % progeny will show wild type phenotype
Explanation:
Parent 1: Normal wings and small eyes : DDee
Parent 2 : Downward wings and normal eyes : ddEE
DDee X ddEE = DdEe ( All have normal wings and normal eyes )
When a F1 individual is test crossed:
DdEe X ddee =
De/de = Parental
dE/de = Parental
DE/de = Recombinant
de/de = Recombinant
Recombination frequency between the two genes is 14% hence DE/de and de/de will each have 7% frequency. Since DE/de ( DdEe ) will give wild type phenotype, it means that 7% progeny will have wild type phenotype.
