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olya-2409 [2.1K]
4 years ago
13

A=b+cp - what is p?

Mathematics
1 answer:
attashe74 [19]4 years ago
6 0

a = b +cp

We have to get p by itself to solve for it.

Start by subtracting b from both sides

a - b = cp

Then we can divide both sides by c to get p

p = (a-b)/c

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I need help pls help
Sauron [17]

Answer:

I could be wrong, but I think it's D

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28-3x%5E2y%29%5E%7B4%7D" id="TexFormula1" title="(-3x^2y)^{4}" alt="(-3x^2y)^{4}" align="absm
Valentin [98]

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

so

-3x^{2*4} y^{1*4}

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well  and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

81x^{8}y^{4}

5 0
3 years ago
Read 2 more answers
Cherie is jogging around a circular track. She
skelet666 [1.2K]

Answer:

Measure of minor angle JOG is 95.5^{\circ}

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.  

\therefore m JG = 200 yards, JO=120 yards.  

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle \angle JOG = \theta.

To calculate the central angle, use the arc length formula as follows.  

Arc\:Length\left(s\right) = r\:\theta  

Where \theta is measured in radian.

Substituting the value,

200=120\:\theta  

Dividing both side by 120,

\dfrac{200}{120}=\theta  

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

\therefore \dfrac{5}{3}=\theta  

Therefore value of central angle is \angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}, since angle is in radian

Now convert radian into degree by using following formula,

1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}

So multiplying \theta with \left(\dfrac{180}{\pi}\right)^{\circ} to convert it into degree.

\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}

Simplifying,

\therefore \theta = 95.49^{circ}

So to nearest tenth, \angle JOG=95.5^{circ}

8 0
4 years ago
if f(x)=2(x)^2+5sqrt(x+2), complete the follwoing statement ( round your answer to the nearest hundreth) : f(0)=_____
Maslowich

Answer:

f(0)=7.07

Step-by-step explanation:

We have the function f(x)=2(x)^2+5\sqrt{(x+2)}

In this case we want to find the value of f0)

To find f(0) you must replace the x in the function with the number 0 and solve as shown below

f(0)=2(0)^2+5\sqrt{(0+2)}

f(0)=0+5\sqrt{(0+2)}

f(0)=5\sqrt{(2)}

Therefore

f(0)=7.07

5 0
4 years ago
If parallel lines a and b are cut by transversal t, then which statement about angles 1 and 2 must be true?
alex41 [277]
Did you not include D or finish writing D since the first three are not right. If one of the possible answers is that they are alternate exterior angles or the same degrees, that would be the answer.
8 0
3 years ago
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