3 years ago

What is the range of the function y= 2e - 1?

1 answer:

8 0

<h3> Answer: All real numbers greater than -1. Step-by-step explanation: We have to find the range of: y= 2e^x-1. We know that e^x lies in (0,∞). Hence, 2e^x lies in (0,∞).</h3>

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3 years ago

This circle is centered at the origin, and the length of its radius is 8. What is

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$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: x² + y² = 64$

____________________________________

$\large \tt Solution \: :$

Standard equation of circle is :

$\qquad \tt \rightarrow \: (x - h) {}^{2} + (y - k) {}^{2} = {r}^{2}$

$\textsf{h = x - coordinate of centre of circle}$

$\textsf{k = y - coordinate of centre of circle}$

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Since the circle is centered at origin, h = k = 0

$\qquad \tt \rightarrow \: (x - 0) {}^{2} + (y - 0) {}^{2} = {8}^{2}$

$\qquad \tt \rightarrow \: {x}^{2} + {y}^{2} = 64$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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