Answer:
A. The value of x is 5
B. The length of each side is 20!
Step-by-step explanation:
For part A., We can determine x by setting these equations to equal each other (as we know that all sides of a square are equal)! See below for how to:

For part B. sub x for 5 to get the side length of one side...

We already know that all sides are equal, so the side length of each side is 20!
<em>Hope I was of assistance!</em> <em><u>#SpreadTheLove <3</u></em>
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
Okay. I got:
FGCE
Step-by-step explanation:
I would try using Photomath or Desmos both great graphing apps!