![\huge\boxed{2\sqrt{29}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B2%5Csqrt%7B29%7D%7D)
Use the distance formula:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Substitute in the known values.
![d=\sqrt{(6-2)^2+(-7-3)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%286-2%29%5E2%2B%28-7-3%29%5E2%7D)
Subtract.
![d=\sqrt{4^2+(-10)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B4%5E2%2B%28-10%29%5E2%7D)
Find the powers.
![d=\sqrt{16+100}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B16%2B100%7D)
Add.
![d=\sqrt{116}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B116%7D)
Find two factors of
.
![d=\sqrt{4*29}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B4%2A29%7D)
Find the two factors of
.
![d=\sqrt{2*2*29}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B2%2A2%2A29%7D)
Move the pair outside the square root.
![d=\boxed{2\sqrt{29}}](https://tex.z-dn.net/?f=d%3D%5Cboxed%7B2%5Csqrt%7B29%7D%7D)
Answer:
What's the problem?
Step-by-step explanation:
No picture or you don't say anything.
*If you analyze the problem closely yo can see the answer is option a
the answer is yes, because they intercept the same arc*
Answer:
a) P(A')=0.7.
b) P(B')=0.75.
c) P(C')=0.4.
d) d) Therefore, we conclude that are A and B mutually exclusive events.
Step-by-step explanation:
From task we know that are:
P(A)=0.3
P(B)=0.25
P(C)=0.6
Therefore, we get calculate the next probabilities:
a) P(A')=1-P(A)
P(A')=1-0.3
P(A')=0.7.
b) P(B')=1-P(B)
P(B')=1-0.25
P(B')=0.75.
c) P(C')=1-P(C)
P(C')=1-0.6
P(C')=0.4.
d) Therefore, we conclude that are A and B mutually exclusive events.