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RideAnS [48]
3 years ago
6

Helpppppp meeee please and thank you

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Answer:

c

Step-by-step explanation:

labwork [276]3 years ago
3 0

Answer It would be D

Step-by-step explanation:

Because it is isosolies M is mediocer so it is option D

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Write a sentence to describe:<br> 20:4
arsen [322]

Answer:

Twenty divided by four equals five.

8 0
3 years ago
Read 2 more answers
A binomial consists of how many terms
patriot [66]
2 because “bi” means 2
5 0
3 years ago
A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a sin
Tatiana [17]

Answer: 1/52

Step-by-step explanation:

A deck of cards contains 52 cards

Red cards are numbered 1,2,3

Blue cards are numbered 1,2,3,4,5,6

Green cards are numbered 1,2

Number of Red card = 3

Number of blue card = 6

Number of Green card = 2

Let Pr(R) = Probability of picking a Red card

Let Pr(B) = probability of picking a blue card

Let Pr(G) = probability of picking a green card

Let Pr(RE) = Probability of picking a red even card

Let Pr(RO) = probability of picking a red odd card

Let Pr(BE) =probability of picking a blue even card

Let Pr(BO) = probability of picking a blue odd card

Let Pr(GE) = probability of picking a green even card

Let Pr(GO) = probability of picking a green odd card

Pr(R) = 3/52

Since we have 3 red cards,

Pr(RE) = 1/3

Pr(RO) =2/3

Pr(B) = 6/52

= 3/26

Since we have 6 blue cards ,

Pr(BE) = 3/6

= 1/2

Pr(BO) = 3/6

= 1/2

Pr (G) = 2/52

= 1/26

Since we have 2 green cards,

Pr(GE) = 1/2

Pr(GO) = 1/2

The probability of picking a Green card and an odd green card is

Pr(G) n pr(GO)

1/26 * 1/2

= 1/52

5 0
3 years ago
. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m
Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0
2 years ago
To subtract two rational expressions that have a common denominator, you simply _____ the numerators.
Gala2k [10]
The answer is subtract.

For example:

\frac{3x^2 - 3}{x+2} - \frac{x^2+6}{x+2}

\frac{3x^2 - 3-x^2-6}{x+2}

\frac{2x^2-9}{x+2}
4 0
3 years ago
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