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nata0808 [166]
3 years ago
12

Please help with this

Mathematics
1 answer:
snow_lady [41]3 years ago
8 0

Answer:

B. -  \frac{9}{8}

Step-by-step explanation:

\huge\frac{ - 2 {a}^{ - 3} {b}^{2}  }{a}  \\  \\ \huge  =  \frac{ - 2  {b}^{2}  }{a \times{a}^{ 3} }   \\  \\ \huge =  \frac{ - 2  {b}^{2}  }{{a}^{ 4} }   \\  \\  \huge =  \frac{ - 2 \times  {3}^{2} }{ {( - 2)}^{4} }  \\  \\   \huge=  \frac{ - 2 \times 9}{16}  \\  \\  \huge  \red{=  -  \frac{9}{8} }

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At Stop n Shop they are selling fried chicken for $1.95 a pound. If Amiyah buys 13.2 pounds how much will she spend?
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Answer:

Step-by-step explanation:

Price of one pound = 1.95

Price of 13.2 pounds = 13.2 x 1.95 = 25.74

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3 years ago
Help me find the slope on the line? Thanks in advance.
Juliette [100K]
(1, 9) and (11,1)

slope
= (9 - 1)/(1 - 11)
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answer
slope = - 0.8
5 0
3 years ago
Read 2 more answers
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Naddika [18.5K]

Answer:

Step-by-step explanation:

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3 years ago
Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and i
Mandarinka [93]

Neither statement 1, nor statement 2 are correct

The given Stephon's statements are;

Statement 1; \mathbf{\lim \limits  _{x \to -3} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to -3} f(x) = 1}

Statement 2; \mathbf{\lim \limits  _{x \to 1} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to 1} f(x) = 1}

The analysis of the graph and reason for the answer

From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement

The limits of the domain and range of the graph includes;

\mathbf{\lim \limits  _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}

f(x) = Defined for -∞ ≤ x < -3

Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write

\mathbf{\lim \limits  _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}

From we above, we have that neither statement 1, nor statement 2 are correct

Learn more about open and closed circles on graph lines

brainly.com/question/8648835

4 0
3 years ago
Does 3/20 have a repeating decimal form
olga_2 [115]

nope, this answer is 0.15

6 0
2 years ago
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