78.3/3.48= 22.5
quotient is the result of division. simply divide 78.3 by 3.48 in a calculator and you get your answer.
Answer:
x ≤ 19
Step-by-step explanation:
The instructions here are probably "solve for x." Please include them.
4 - x + 6^2 ≥ 21
becomes 4 - x + 36 ≥ 21
Now combine like terms. 4 and 36 combine to 40: 40 - x ≥ 21, and so:
19 - x ≥ 0
Adding x to both sies results in
x ≤ 19
Please, include the instructions when you post a question. Thanks.
Since there are only two sides (heads & tails) to a coin:
Probability (as fraction) - 1/2
Probability (as percent) - 1/2 x 100 = 50%
Probability (as decimal) - 1 x 50/2 x 50 = 50/100 = 0.5
(P.S. Please mark this answer as the brainliest answer... Thank You)
Observe the given data distribution table carefully.
The 5th class interval is given as,
The upper limit (UL) and lower limit (LL) of this interval are,
Thus, the upper-class limit of this 5th class is 17.4.
Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.
First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
A cross-section of an oblique cylinder will be a small right cylinder with the same base surface area and a height as small as possible.
I guess the oblique cylinder has height h and it is divided into many (probably 10) cross-sections.
Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.
Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).
Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.
Option D: </span><span>1 2 πr2h
Here, we have the same notation issue as before. I think you meant (1/2)</span>·<span>πr2h.
Here, your oblique cylinder height h should be divided into only 2 cross-sections. Now, we said the cross-section's height should be the smallest as possible, so an oblique cylinder divided only into two pieces doesn't sound good.
Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>
