Question

Find the distance between (5,5) and (8,1)

Answer 1

$here \: is \: your \: answer...$

Step-by-step explanation:

Let (x1,y1) = (5,5) and (x2,y2) = (8,1)

By using distance formula,

$d \: = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

$d = \sqrt{ {(8 - 5)}^{2} + {(1 - 5)}^{2} }$

$d = \sqrt{ {(3)}^{2} + {( - 4)}^{2} }$

$d = \sqrt{9 + 16}$

$d = \sqrt{25}$

$d = 5 \: units$

Therefore, the distance between (5,5) and (8,1) is 5 units

Answer 2

Answer:

5

Step-by-step explanation:

Imagine a triangle with two of the corner points being the points (5,5) and (8,1)

The length and width would be 3 and 4 to find the hypotenuse (distance) do

3^2+4^2=x^2

9+16=x^2

25=x^2

x=5